Theorem of Proth
In Mathematical, the theorem of Proth in Théorie of the numbers is a Test of primality for the Nombres of Proth.
This theorem states that for a number of Proth p , therefore form K 2 N + 1 with K a naturalness and K < 2 N , if there exists an entirety has such as:
then p is first.
This test is practical because if p is first, a has chosen has approximately 50% of chances to prove the primality of p . Moreover it is remarkably useful to show the conjecture of Sierpinski.
Numerical examples
The first seven numbers of Proth correspond to:
-
P 0 = 21 + 1 = 3
- P 1 = 22 + 1 = 5
- P 2 = 23 + 1 = 9
- P 3 = 3 × 22 + 1 = 13
- P 4 = 24 + 1 = 17
- P 5 = 3 × 23 + 1 = 25
- P 6 = 25 + 1 = 33
- P 1 = 22 + 1 = 5
Examples of the theorem:
-
For p = 3,21 + 1 = 3 what is divisible by 3; thus 3 is first.
- For p = 5,32 + 1 = 10 what is divisible by 5; thus 5 is first.
- For p = 13,56 + 1 = 15626 what is divisible by 13; thus 13 are first.
- For p = 9, which is not first, there does not exist has such as has 4 + 1 is divisible by 9.
History
-
the mathematician François Proth (1852 - 1879) discovered the theorem in 1878.
See too
External bonds
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Mathworld
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