Theorem of Proth

In Mathematical, the theorem of Proth in Théorie of the numbers is a Test of primality for the Nombres of Proth.

This theorem states that for a number of Proth p , therefore form K 2 N + 1 with K a naturalness and K < 2 N , if there exists an entirety has such as:

a^ {(p-1) /2} \ equiv -1 \ pmod {p} \, \!

then p is first.

This test is practical because if p is first, a has chosen has approximately 50% of chances to prove the primality of p . Moreover it is remarkably useful to show the conjecture of Sierpinski.

Numerical examples

The first seven numbers of Proth correspond to:

P 0 = 21 + 1 = 3

P 1 = 22 + 1 = 5
P 2 = 23 + 1 = 9
P 3 = 3 × 22 + 1 = 13
P 4 = 24 + 1 = 17
P 5 = 3 × 23 + 1 = 25
P 6 = 25 + 1 = 33

Examples of the theorem:

  • For p = 3,21 + 1 = 3 what is divisible by 3; thus 3 is first.

  • For p = 5,32 + 1 = 10 what is divisible by 5; thus 5 is first.
  • For p = 13,56 + 1 = 15626 what is divisible by 13; thus 13 are first.
  • For p = 9, which is not first, there does not exist has such as has 4 + 1 is divisible by 9.

History

  • the mathematician François Proth (1852 - 1879) discovered the theorem in 1878.

See too

External bonds

  • Mathworld

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