Conservation of the electric charge

Introduction

The conservation of the electric charge is a physical Principe. It expresses that the electric Charge of a system is a Invariant, i.e. it cannot change, some are the transformations undergone by this system.

Thus, during a chemical reaction, the total sum of the loads of the concerned species is preserved between the produced Réactifs and . In the same way, at the time of a collision between atoms, ions or molecules, of a radioactive decay, or an exchange energy - Matter, it is the same.

Conservation equation of the load in electromagnetism

If \ vec {J} indicates the voluminal Vecteur density of current and \ rho the voluminal Densité of load:

It is a particular case of the matter assessment for a preserved quantity.

It is also consequence of the Maxwell's equations; on the basis of the equation of Maxwell-Amp:

\ vec {belch} \, \ vec {B} - \ frac {1} {c^ {2}} \, \ frac {\ partial \, \ vec {E}} {\ partial \, T} = \ mu_ {0} \, \ vec {J}

then by taking the Divergence (knowing that the divergence of a Rotationnel is null):

- \ frac {1} {c^ {2}} \, \ frac {\ partial \, div \, \ vec {E}} {\ partial \, T} = \ mu_ {0} \, div \, \ vec {J}

and by finally using the equation of Maxwell-Gauss:

div \, \ vec {E} = \ mu_ {0} \, c^ {2} \, \ rho

the announced result is obtained.

Some consequences

  • In permanent mode, i.e \ frac {\ partial} {\ partial \, T} =0, one has div \, \ vec {J} =0: \ vec {J} is then a zero divergence field. Thus, while integrating on a closed surface, for example a piece of discussion thread, one can find the law of the nodes of Kirchhoff concerning the conservation of the intensity.

  • only Let us consider a conducting material of homogeneous Conductivité \ gamma in the universe. Conservation equation of the load and Law of Ohm \ vec {J} = \ gamma \, \ vec {E} one draws, \ gamma being supposed homogeneous: \ gamma \, div \, \ vec {E} + \ frac {\ partial \, \ rho} {\ partial \, T} =0. By once again using the equation of Maxwell-Gauss one obtains the temporal evolution of \ rho: \ frac {\ partial \, \ rho} {\ partial \, T} + \ gamma \, \ mu_ {0} \, c^ {2} \, \ rho=0.
Thus, \ rho tends exponentially towards 0 with a time-constant \ frac {1} {\ gamma \, \ mu_ {0} \, c^ {2}} which is about 10^ {- 18} \, s for a metal of conductivity about 10^7 \, S.m^ {- 1} : it cannot thus remain of voluminal density of load in a good driver. This can appear paradoxical if the driver had a nonnull total load initially! One can answer it by affirming that this total load is found in the form of a surface Densité of load at the edge of the driver, the voluminal Densité of load inside being quite null.

See too

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